NY-13: McMahon Crushing Harrison in Dem Primary Poll

SurveyUSA (8/18-19, registered Dem voters):

Mike McMahon (D): 64

Steve Harrison (D): 18

Undecided: 18

(MoE: ±4.3%)

Big lead for McMahon. Keep in mind that this poll is of registered, and not likely Dem voters, so a different screen might produce a somewhat different result.

McMahon, an NYC Councilman, has a pretty consistent lead among all age brackets and both men and women. Somewhat amusingly, Steve Harrison’s strongest performance in the crosstabs comes from conservative Democrats, who give him 27% to McMahon’s 57%.

Primary: September 9th

6 thoughts on “NY-13: McMahon Crushing Harrison in Dem Primary Poll”

  1. But I’d be even more impressed if McMahon was polled against one of the Republican candidates in NY-13, just to show the chances of a Democrat picking up strongly GOP Staten Island.

  2. I’m hoping for Harrison. I don’t think we can lose this district and I think Harrison would make a much better congressman, he also has been running a decent campaign unlike other progressive challengers (Fallon, Thomas, etc).

    But I guess it won’t happen. Ah well, McMahon will blow out the Republicans candidate.

  3. definetly glad to see that this is one race where Democrats aren’t shooting themselves in the foot.  

    Lets go McMahon.  

  4. Plan on writing something soon about this race but I’ll just give this comment now.

    This is a race with practically no interest whatsoever. The weird crosstabs may very well come from the large number of people who barely know (or care) who the candidates are.  Even the Obama-Hillary contest only garnered about 30,000 votes in the entire 13th district.  A district where Democrats have a registration edge.  It is doubtful turnout will be that high.

    The race will come down to organization and candidates literally dragging voters to the polls.  While it is a race McMahon SHOULD win and WOULD win if it were on the same primary ballot with a well publicized up ballot race in a VERY low turnout election literally anything is possible.

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